Question

Oblicz okres i częstotliwosc obrotów 26calowego koła roweru jadacego z prędkoscia 18 km / h

Answer 1

V=2πr/T

T=2πr/V

T=t/n

ni=1/T

V=2πr*ni

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T=?

ni=?

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V=12km/h=12* 1000/3600=3 i 1/3 m/s=10/3m/s

26cali=66,04cm

d=66,04cm

r=33,02cm

l=2πr

l=2*3,14*33,02

l=207,3656cm=2,073656m≈2m

 

1m---10/3

2m---x

x=2/10/3

x=2*3/10

x=6/10

x=3/5

 

T=3/5[s]

 

ni=1/T

ni=1/3/5

ni=1*5/3

 

ni=5/3 [Hz]